# Copyright (c) 2009 Google Inc. All rights reserved.
# Copyright (c) 2009 Apple Inc. All rights reserved.
#
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# modification, are permitted provided that the following conditions are
# met:
#
#     * Redistributions of source code must retain the above copyright
# notice, this list of conditions and the following disclaimer.
#     * Redistributions in binary form must reproduce the above
# copyright notice, this list of conditions and the following disclaimer
# in the documentation and/or other materials provided with the
# distribution.
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# contributors may be used to endorse or promote products derived from
# this software without specific prior written permission.
#
# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
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import re


def plural(noun):
    # This is a dumb plural() implementation that is just enough for our uses.
    if re.search('h$', noun):
        return noun + 'es'
    else:
        return noun + 's'


def pluralize(noun, count):
    if count != 1:
        noun = plural(noun)
    return '%d %s' % (count, noun)


def join_with_separators(list_of_strings, separator=', ', only_two_separator=' and ', last_separator=', and '):
    if not list_of_strings:
        return ''
    if len(list_of_strings) == 1:
        return list_of_strings[0]
    if len(list_of_strings) == 2:
        return only_two_separator.join(list_of_strings)
    return '%s%s%s' % (separator.join(list_of_strings[:-1]), last_separator, list_of_strings[-1])