blob: 2a91882d019fc2f718796f43407762ef359a3921 [file] [log] [blame]
"""Better tokenizing for coverage.py."""
import codecs, keyword, re, sys, token, tokenize
from coverage.backward import StringIO # pylint: disable=W0622
def phys_tokens(toks):
"""Return all physical tokens, even line continuations.
tokenize.generate_tokens() doesn't return a token for the backslash that
continues lines. This wrapper provides those tokens so that we can
re-create a faithful representation of the original source.
Returns the same values as generate_tokens()
"""
last_line = None
last_lineno = -1
last_ttype = None
for ttype, ttext, (slineno, scol), (elineno, ecol), ltext in toks:
if last_lineno != elineno:
if last_line and last_line[-2:] == "\\\n":
# We are at the beginning of a new line, and the last line
# ended with a backslash. We probably have to inject a
# backslash token into the stream. Unfortunately, there's more
# to figure out. This code::
#
# usage = """\
# HEY THERE
# """
#
# triggers this condition, but the token text is::
#
# '"""\\\nHEY THERE\n"""'
#
# so we need to figure out if the backslash is already in the
# string token or not.
inject_backslash = True
if last_ttype == tokenize.COMMENT:
# Comments like this \
# should never result in a new token.
inject_backslash = False
elif ttype == token.STRING:
if "\n" in ttext and ttext.split('\n', 1)[0][-1] == '\\':
# It's a multiline string and the first line ends with
# a backslash, so we don't need to inject another.
inject_backslash = False
if inject_backslash:
# Figure out what column the backslash is in.
ccol = len(last_line.split("\n")[-2]) - 1
# Yield the token, with a fake token type.
yield (
99999, "\\\n",
(slineno, ccol), (slineno, ccol+2),
last_line
)
last_line = ltext
last_ttype = ttype
yield ttype, ttext, (slineno, scol), (elineno, ecol), ltext
last_lineno = elineno
def source_token_lines(source):
"""Generate a series of lines, one for each line in `source`.
Each line is a list of pairs, each pair is a token::
[('key', 'def'), ('ws', ' '), ('nam', 'hello'), ('op', '('), ... ]
Each pair has a token class, and the token text.
If you concatenate all the token texts, and then join them with newlines,
you should have your original `source` back, with two differences:
trailing whitespace is not preserved, and a final line with no newline
is indistinguishable from a final line with a newline.
"""
ws_tokens = [token.INDENT, token.DEDENT, token.NEWLINE, tokenize.NL]
line = []
col = 0
source = source.expandtabs(8).replace('\r\n', '\n')
tokgen = tokenize.generate_tokens(StringIO(source).readline)
for ttype, ttext, (_, scol), (_, ecol), _ in phys_tokens(tokgen):
mark_start = True
for part in re.split('(\n)', ttext):
if part == '\n':
yield line
line = []
col = 0
mark_end = False
elif part == '':
mark_end = False
elif ttype in ws_tokens:
mark_end = False
else:
if mark_start and scol > col:
line.append(("ws", " " * (scol - col)))
mark_start = False
tok_class = tokenize.tok_name.get(ttype, 'xx').lower()[:3]
if ttype == token.NAME and keyword.iskeyword(ttext):
tok_class = "key"
line.append((tok_class, part))
mark_end = True
scol = 0
if mark_end:
col = ecol
if line:
yield line
def source_encoding(source):
"""Determine the encoding for `source` (a string), according to PEP 263.
Returns a string, the name of the encoding.
"""
# Note: this function should never be called on Python 3, since py3 has
# built-in tools to do this.
assert sys.version_info < (3, 0)
# This is mostly code adapted from Py3.2's tokenize module.
cookie_re = re.compile(r"coding[:=]\s*([-\w.]+)")
# Do this so the detect_encode code we copied will work.
readline = iter(source.splitlines(True)).next
def _get_normal_name(orig_enc):
"""Imitates get_normal_name in tokenizer.c."""
# Only care about the first 12 characters.
enc = orig_enc[:12].lower().replace("_", "-")
if re.match(r"^utf-8($|-)", enc):
return "utf-8"
if re.match(r"^(latin-1|iso-8859-1|iso-latin-1)($|-)", enc):
return "iso-8859-1"
return orig_enc
# From detect_encode():
# It detects the encoding from the presence of a utf-8 bom or an encoding
# cookie as specified in pep-0263. If both a bom and a cookie are present,
# but disagree, a SyntaxError will be raised. If the encoding cookie is an
# invalid charset, raise a SyntaxError. Note that if a utf-8 bom is found,
# 'utf-8-sig' is returned.
# If no encoding is specified, then the default will be returned. The
# default varied with version.
if sys.version_info <= (2, 4):
default = 'iso-8859-1'
else:
default = 'ascii'
bom_found = False
encoding = None
def read_or_stop():
"""Get the next source line, or ''."""
try:
return readline()
except StopIteration:
return ''
def find_cookie(line):
"""Find an encoding cookie in `line`."""
try:
line_string = line.decode('ascii')
except UnicodeDecodeError:
return None
matches = cookie_re.findall(line_string)
if not matches:
return None
encoding = _get_normal_name(matches[0])
try:
codec = codecs.lookup(encoding)
except LookupError:
# This behaviour mimics the Python interpreter
raise SyntaxError("unknown encoding: " + encoding)
if bom_found:
# codecs in 2.3 were raw tuples of functions, assume the best.
codec_name = getattr(codec, 'name', encoding)
if codec_name != 'utf-8':
# This behaviour mimics the Python interpreter
raise SyntaxError('encoding problem: utf-8')
encoding += '-sig'
return encoding
first = read_or_stop()
if first.startswith(codecs.BOM_UTF8):
bom_found = True
first = first[3:]
default = 'utf-8-sig'
if not first:
return default
encoding = find_cookie(first)
if encoding:
return encoding
second = read_or_stop()
if not second:
return default
encoding = find_cookie(second)
if encoding:
return encoding
return default