|  | // RUN: %clang_cc1 -verify -std=c++11 %s | 
|  |  | 
|  | using T = int[]; | 
|  |  | 
|  | void f() { | 
|  | int *p = &(int&)(int&&)0; // expected-warning {{temporary whose address is used as value of local variable 'p' will be destroyed at the end of the full-expression}} | 
|  |  | 
|  | int *q = (int *const &)T{1, 2, 3}; // expected-warning {{temporary whose address is used as value of local variable 'q' will be destroyed at the end of the full-expression}} | 
|  |  | 
|  | // FIXME: We don't warn here because the 'int*' temporary is not const, but | 
|  | // it also can't have actually changed since it was created, so we could | 
|  | // still warn. | 
|  | int *r = (int *&&)T{1, 2, 3}; | 
|  |  | 
|  | // FIXME: The wording of this warning is not quite right. There are two | 
|  | // temporaries here: an 'int* const' temporary that points to the array, and | 
|  | // is lifetime-extended, and an array temporary that the pointer temporary | 
|  | // points to, which doesn't live long enough. | 
|  | int *const &s = (int *const &)T{1, 2, 3}; // expected-warning {{temporary bound to local reference 's' will be destroyed at the end of the full-expression}} | 
|  | } | 
|  |  | 
|  | // PR38355 | 
|  | void g() { | 
|  | const int a[] = {a[0]}; | 
|  | const int b[] = {a[0]}; | 
|  | } |