| // RUN: %clang_cc1 -std=c++11 -triple i386-windows-msvc \ |
| // RUN: -aux-triple nvptx-nvidia-cuda -fsyntax-only -verify %s |
| |
| // RUN: %clang_cc1 -std=c++11 -triple nvptx-nvidia-cuda \ |
| // RUN: -aux-triple i386-windows-msvc -fsyntax-only \ |
| // RUN: -fcuda-is-device -verify %s |
| |
| // RUN: %clang_cc1 -std=c++11 -triple nvptx-nvidia-cuda \ |
| // RUN: -aux-triple x86_64-linux-gnu -fsyntax-only \ |
| // RUN: -fcuda-is-device -verify -verify-ignore-unexpected=note \ |
| // RUN: -DEXPECT_ERR %s |
| |
| // CUDA device code should inherit the host's calling conventions. |
| |
| template <class T> |
| struct Foo; |
| |
| template <class T> |
| struct Foo<T()> {}; |
| |
| // On x86_64-linux-gnu, this is a redefinition of the template, because the |
| // __fastcall calling convention doesn't exist (and is therefore ignored). |
| #ifndef EXPECT_ERR |
| // expected-no-diagnostics |
| #else |
| // expected-error@+4 {{redefinition of 'Foo}} |
| // expected-warning@+3 {{calling convention '__fastcall' ignored}} |
| #endif |
| template <class T> |
| struct Foo<T __fastcall()> {}; |
