| // RUN: %clang_cc1 -verify -std=c++11 %s |
| |
| using T = int[]; |
| |
| void f() { |
| int *p = &(int&)(int&&)0; // expected-warning {{temporary whose address is used as value of local variable 'p' will be destroyed at the end of the full-expression}} |
| |
| int *q = (int *const &)T{1, 2, 3}; // expected-warning {{temporary whose address is used as value of local variable 'q' will be destroyed at the end of the full-expression}} |
| |
| // FIXME: We don't warn here because the 'int*' temporary is not const, but |
| // it also can't have actually changed since it was created, so we could |
| // still warn. |
| int *r = (int *&&)T{1, 2, 3}; |
| |
| // FIXME: The wording of this warning is not quite right. There are two |
| // temporaries here: an 'int* const' temporary that points to the array, and |
| // is lifetime-extended, and an array temporary that the pointer temporary |
| // points to, which doesn't live long enough. |
| int *const &s = (int *const &)T{1, 2, 3}; // expected-warning {{temporary bound to local reference 's' will be destroyed at the end of the full-expression}} |
| } |
| |
| // PR38355 |
| void g() { |
| const int a[] = {a[0]}; |
| const int b[] = {a[0]}; |
| } |