| #include <stdlib.h> |
| #include <ctype.h> |
| |
| /* |
| grammar: |
| |
| Start = Expr ';' |
| Expr = Or | Or '?' Expr ':' Expr |
| Or = And | Or '||' And |
| And = Eq | And '&&' Eq |
| Eq = Rel | Eq '==' Rel | Eq '!=' Rel |
| Rel = Add | Rel '<=' Add | Rel '>=' Add | Rel '<' Add | Rel '>' Add |
| Add = Mul | Add '+' Mul | Add '-' Mul |
| Mul = Prim | Mul '*' Prim | Mul '/' Prim | Mul '%' Prim |
| Prim = '(' Expr ')' | '!' Prim | decimal | 'n' |
| |
| internals: |
| |
| recursive descent expression evaluator with stack depth limit. |
| for binary operators an operator-precedence parser is used. |
| eval* functions store the result of the parsed subexpression |
| and return a pointer to the next non-space character. |
| */ |
| |
| struct st { |
| unsigned long r; |
| unsigned long n; |
| int op; |
| }; |
| |
| static const char *skipspace(const char *s) |
| { |
| while (isspace(*s)) s++; |
| return s; |
| } |
| |
| static const char *evalexpr(struct st *st, const char *s, int d); |
| |
| static const char *evalprim(struct st *st, const char *s, int d) |
| { |
| char *e; |
| if (--d < 0) return ""; |
| s = skipspace(s); |
| if (isdigit(*s)) { |
| st->r = strtoul(s, &e, 10); |
| if (e == s || st->r == -1) return ""; |
| return skipspace(e); |
| } |
| if (*s == 'n') { |
| st->r = st->n; |
| return skipspace(s+1); |
| } |
| if (*s == '(') { |
| s = evalexpr(st, s+1, d); |
| if (*s != ')') return ""; |
| return skipspace(s+1); |
| } |
| if (*s == '!') { |
| s = evalprim(st, s+1, d); |
| st->r = !st->r; |
| return s; |
| } |
| return ""; |
| } |
| |
| static int binop(struct st *st, int op, unsigned long left) |
| { |
| unsigned long a = left, b = st->r; |
| switch (op) { |
| case 0: st->r = a||b; return 0; |
| case 1: st->r = a&&b; return 0; |
| case 2: st->r = a==b; return 0; |
| case 3: st->r = a!=b; return 0; |
| case 4: st->r = a>=b; return 0; |
| case 5: st->r = a<=b; return 0; |
| case 6: st->r = a>b; return 0; |
| case 7: st->r = a<b; return 0; |
| case 8: st->r = a+b; return 0; |
| case 9: st->r = a-b; return 0; |
| case 10: st->r = a*b; return 0; |
| case 11: if (b) {st->r = a%b; return 0;} return 1; |
| case 12: if (b) {st->r = a/b; return 0;} return 1; |
| } |
| return 1; |
| } |
| |
| static const char *parseop(struct st *st, const char *s) |
| { |
| static const char opch[11] = "|&=!><+-*%/"; |
| static const char opch2[6] = "|&===="; |
| int i; |
| for (i=0; i<11; i++) |
| if (*s == opch[i]) { |
| /* note: >,< are accepted with or without = */ |
| if (i<6 && s[1] == opch2[i]) { |
| st->op = i; |
| return s+2; |
| } |
| if (i>=4) { |
| st->op = i+2; |
| return s+1; |
| } |
| break; |
| } |
| st->op = 13; |
| return s; |
| } |
| |
| static const char *evalbinop(struct st *st, const char *s, int minprec, int d) |
| { |
| static const char prec[14] = {1,2,3,3,4,4,4,4,5,5,6,6,6,0}; |
| unsigned long left; |
| int op; |
| d--; |
| s = evalprim(st, s, d); |
| s = parseop(st, s); |
| for (;;) { |
| /* |
| st->r (left hand side value) and st->op are now set, |
| get the right hand side or back out if op has low prec, |
| if op was missing then prec[op]==0 |
| */ |
| op = st->op; |
| if (prec[op] <= minprec) |
| return s; |
| left = st->r; |
| s = evalbinop(st, s, prec[op], d); |
| if (binop(st, op, left)) |
| return ""; |
| } |
| } |
| |
| static const char *evalexpr(struct st *st, const char *s, int d) |
| { |
| unsigned long a, b; |
| if (--d < 0) |
| return ""; |
| s = evalbinop(st, s, 0, d); |
| if (*s != '?') |
| return s; |
| a = st->r; |
| s = evalexpr(st, s+1, d); |
| if (*s != ':') |
| return ""; |
| b = st->r; |
| s = evalexpr(st, s+1, d); |
| st->r = a ? b : st->r; |
| return s; |
| } |
| |
| unsigned long __pleval(const char *s, unsigned long n) |
| { |
| struct st st; |
| st.n = n; |
| s = evalexpr(&st, s, 100); |
| return *s == ';' ? st.r : -1; |
| } |